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Byju's Answer
Standard XII
Mathematics
Asymptotes
In the hyperb...
Question
In the hyperbola
16
x
2
−
9
y
2
=
144
, find the equation to the diameter which is conjugate to the diameter whose equation is
x
=
2
y
.
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Solution
Two diameters of a hyperbola
y
=
m
x
and
y
=
m
1
x
are said to be conjugate if they follow the relation
m
m
1
=
b
2
a
2
So here,
m
=
1
2
⇒
1
2
m
1
=
16
9
⇒
m
1
=
32
9
Hence the equation of other diameter is
y
=
32
9
x
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