In the ideal YDSE when a glass plate (RI=1.5) of thickness t is introduced in path of one of interfering beams , the intensity at the position where central maximum occurred previously remains unchanged. The minimum thickness of glass plate is :
A
λ
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B
3λ
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C
4λ
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D
2λ
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Solution
The correct option is D2λ Shift=Dd(μ−1)t=Dλd⇒t=λμ−1=2λHence,optionDcorrectanswer.