Question

In the ionic equation, $Bi{O}_3^{-}+6H^{+}+x{e}^{-}\to B{i}^{3+}+3H_{2}O$, the value of x is:

• A. $6$
• B. $2$
• C. $4$
• D. $3$

Answer 1

The correct option is B $2$

In the above reaction, we are required to balance charges on both sides of the reaction.

LHS: Net charge $=-1+6-x$

RHS: Net charge $=+3+0$

LHS = RHS

$-1+6-x=+3+0⟹5-x=3⟹x=5-3⟹x=2$

Hence, Option B is the correct answer.