Question

In the joining circuit shown the potential difference between point $A$ and $B$ will be.

• A. $\frac{8}{9}V$
• B. $\frac{8}{3}V$
• C. $\frac{2}{3}V$
• D. $2V$

Answer 1

The correct option is B $\frac{8}{3}V$

$10+5=15\Omega$

$\frac{15\times 15}{15+15}=\frac{15\times 15}{30}$

$I=\frac{2\times 2}{15}=\frac{4}{15}A$

$I^1=\frac{4}{15}\times \frac{15}{30}$

$=\frac{2}{15}\times 20=\frac{8}{3}V$