In the laboratory preparation of $H C l$ gas, the drying agent used conventionally (conc. $H_{2} S O_{4}$ ) can be replaced by quicklime & phosphorous pentoxide.

True

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False

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Solution

The correct option is B
False

Quicklime and Phosphrous pentoxide $P_{2} O_{5}$ cannot be used since they react with hydrogen chloride forming the respective chloride.

$C a O + 2 H C l \to C a C l_{2} + H_{2} O 2 P_{2} O_{5} + 3 H C l \to P O C l_{3} + 3 H P O_{3}$

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Similar questions

The drying agent used conventionally (conc $H_{2} S O_{4}$ ) can be replaced by quicklime & phosphorous pentoxide.

(a) Draw a labelled diagram for the laboratory preparation of hydrogen chloride gas.
(b) Give the balanced equation for the reaction.
(c) Name the drying agent used in drying hydrogen chloride gas.
(d) Phosphorus pentoxide and calcium oxide are good drying agents but they cannot be used to dry hydrogen chloride gas. Why?

Q. (i) How is ammonia gas prepared in laboratory starting from NH₄Cl? State the conditions and balanced equation for the preparation.
(ii) How is gas collected in a gas jar?
(iii) Name the substance used for drying ammonia gas. Why cannot substances such as conc. H₂SO₄, anhydrous calcium chloride and phosphorus pentoxide be used for drying ammonia gas?

Why is conc. HCl not used in place of conc. $H_{2} S O_{4}$ in the laboratory preparation of nitric acid?

Phosphorous pentoxide and concentrated sulphuric acid can be classified as basic drying agents.

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In the laboratory preparation of HCl gas, the drying agent used conventionally (conc. H2SO4) can be replaced by quicklime & phosphorous pentoxide.

The correct option is B False Quicklime and Phosphrous pentoxide P2O5 cannot be used since they react with hydrogen chloride forming the respective chloride. CaO+2HCl→CaCl2+H2O2P2O5+3HCl→POCl3+3HPO3

In the laboratory preparation of $H C l$ gas, the drying agent used conventionally (conc. $H_{2} S O_{4}$ ) can be replaced by quicklime & phosphorous pentoxide.

The correct option is B
False

Quicklime and Phosphrous pentoxide $P_{2} O_{5}$ cannot be used since they react with hydrogen chloride forming the respective chloride.

$C a O + 2 H C l \to C a C l_{2} + H_{2} O 2 P_{2} O_{5} + 3 H C l \to P O C l_{3} + 3 H P O_{3}$