In the Lassaignes test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

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Solution

$F e s O_{4} + N a O H ⟶ F e (O H)_{2} + N a_{2} S O_{4}$

$6 N a C N + F e (O H)_{2} ⟶ N a_{4} [F e (C N)_{6}] S o d i u m f e r r o c y a n i d e$

$3 N a_{4} [F e (C N)_{6}] + 4 F e C l_{3} ⟶ F e_{4} [F e (C N)_{6}]_{3} + 12 N a C l F e r r i c f e r r o c y a n i d e (P r u s s i a n b l u e)$

$L a s s a i g n e t e s t$ is used for the estimation of nitrogen in an organic compound. Sodium fusion extract is boiled with ferrous sulphate and acidified with sulphuric acid. Sodium cyanide reacts with ferrous sulphate and forms sodium hexacyanoferrate(II). On heating with sulphuric acid, some ferrous is oxidized to ferric hexacyanoferate (II) $F e_{4} [F e (C N)_{6}]_{3}$ which is Prussian blue in colour.

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(a) $N a_{4} [F e (C N)_{6}]$ (b) $F e_{4} [F e (C N)_{6}]^{3}$ (c) $F e_{2} [F e (C N)_{6}]$ (d) $F e_{3} [F e (C N)_{6}]_{4}$

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