In the $L C R$ circuit, the voltmeter and ammeter readings are

$200 V, 20 A$

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$200 V, 50 A$

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$1000 V, 20 A$

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$100 V, 20 A$

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Solution

The correct option is C
$1000 V, 20 A$

Voltage across the inductor and capacitor cancel out as they are equal in magnitude and out of phase with each other.
Hence voltage across resistance $R$ is $1000 V$ and
current $I = \frac{V}{R} = \frac{1000}{50} = 20 A$

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