Question

In the Lewis dot structure $X:$,the predictable oxidation number is :

• A. $+1$
• B. $-1$
• C. $+2$
• D. $-2$
• E. $+3$

Answer 1

Answer: (C)

$+2$

$X:$ has two valence electrons.

After drawing the Lewis Dot structure, the lone pair on $X$ represents the two valence electrons.

So, $X$ now has two valence electrons. $X$ wants to get rid of these two electrons from the outermost orbit to complete its octet.

Thus, when $X$ gives away the two valence electrons, its oxidation number becomes $+2$, that is, it becomes a dipositive ion.

Thus option $C$ is the correct answer.