In the line $2 x + 3 y = 1$ touches the parabola $y^{2} = 4 a (x + a)$ , then the length of its latus rectum is

\frac{8}{9}

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\frac{8}{13}

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4

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\frac{4}{9}

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\frac{4}{13}

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2 x + 3 y = 1

y^{2} = 4 a x

{(2 x + 3 y + 2)}^{2} = 4 (3 x + 2 y + 3)

4

y^{2} = 4 a x

4 a

If the parabola $y^{2} = 4 a x$ passes through (-3,2), then length of its latus rectum is

y = | x - 3 |

y^{2} = λ (x - 4), λ > 0,

y^{2} = 4 a x

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In the line 2x+3y=1 touches the parabola y2=4a(x+a), then the length of its latus rectum is