In the lowest orbit,the binding energy of an electron in hydrogen atom is $13.6 e V$ . The energy required to take out the electron from the lower three orbits (in $e V$ ) will be

13.6, 6.8, 8.4

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13.6, 10.2, 3.4

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3.6, 27.2, 40.8

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13.6, 3.4, 1.5

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Solution

The correct option is D $13.6, 3.4, 1.5$
Binding energy of an electron in $n^{t h}$ orbit in an atom $= 13.6 \frac{z^{2}}{n^{2}} e V$
In hydrogen, $z = 1$

$B i n d i n g E n e r g y f r o m l o w e s t o r b i t (n = 1) = 13.6 e V B i n d i n g E n e r g y f r o m 2 n d l o w e s t o r b i t (n = 2) = 3.4 e V b i n d i n g E n e r g y f r o m 3 r d l o w e s t o r b i t (n = 3) = 1.5 e V$

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