Question

In the magnetic meridian of a certain place the horizontal component of earth's magnetic field is $0.25$G and dip angle is ${60}^0$. The magnetic field of the earth at this location is

• A. $0.50$G
• B. $0.52$G
• C. $0.54$G
• D. $0.56$G

Answer 1

The correct option is A $0.50$G

Here, $H_E=0.25G$ and $cos\delta =\frac{H_E}{B_E}$
$\therefore$ The magnetic field of earth at the given location is
$B_E=\frac{H_E}{cos{60}^0}=\frac{0.25}{1/2}=0.50G$