Question

In the magnetic meridian of a certain place the horizontal component of earth's magnetic field is $0.25$G and dip angle is ${60}^o$. The magnetic field of the earth at this location is?

• A. $0.50$G
• B. $0.52$G
• C. $0.54$G
• D. $0.56$G

Answer 1

The correct option is A $0.50$G

Here, $H_E=0.25$G and $\cos \delta =\frac{H_E}{B_E}$

$\therefore$ The magnetic field of earth at the given location is

$B_E=\frac{H_E}{\cos {60}^o}=\frac{0.25}{1/2}=0.50$G.