In the manufacture of Ammonia by Haber's process, the condition which would give maximum yield is: $N_{2} + 3 H_{2} ⇌ 2 N H_{3} + Q k c a l$ .

High temperature, high pressure and high concentrations of the reactants

No worries! We‘ve got your back. Try BYJU‘S free classes today!

High temperature, low pressure and low concentrations of the reactants

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Low temperature and high pressure

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Low temperature, low pressure and low concentration of

H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Low temperature and high pressure
$N_{2} + 3 H_{2} ⇌ 2 N H_{3} + Q K c a l$
(i) since process of making ammonia is exothermic process low temperature is favourable
(ii) No. of mole of gase is reactant side is more than product side so high pressure is favourable in production of Ammonia
According to above two condition low temp and high pressure is favourable
$\Rightarrow$ Option C is correct.

Suggest Corrections

Similar questions

Q. In the formation of the

N H_{3}

by the Haber`s process which condition will give maximum yield the equation is as

N_{2} (g)

3 H_{2} (g) ⇌ 2 N H_{3} (g)

Δ H = - Q k c a l

, where Q is positive.

Manufacture of ammonia from the elements is represented as,

N₂ + 3H₂ ⇌ 2NH₃ + 22.4 k cals. The maximum yield of ammonia will be obtained when the process is made to take place:

Q. In the reaction,

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g) + X cal

, most favourable conditions of temperature and pressure for greater yield of

S O_{3}

are:

Q. Given reaction is

3 X (g) + Y (g) ⇌ 3 Z (g)

Δ H = + 35 k J

Which conditions will give the highest yield of

Z

at equilibrium?

Q. Which of the following conditions will favour the maximum formation of the product in the reaction:

A_{2}

(g) +

B_{2}

(g)

⇌

X_{2}

(g)

△_{r}

H= -X kJ

Join BYJU'S Learning Program

In the manufacture of Ammonia by Haber's process, the condition which would give maximum yield is: N2+3H2⇌2NH3+Q kcal.

In the manufacture of Ammonia by Haber's process, the condition which would give maximum yield is: $N_{2} + 3 H_{2} ⇌ 2 N H_{3} + Q k c a l$ .