In the manufacture of bromine from sea water, the mother liquor containing bromides is treated with

carbon dioxide

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chlorine

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iodine

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sulphur dioxide.

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Solution

The correct option is B chlorine
Bromide in the mother liquor $(c o n t a i n i n g M g B r_{2}$ is oxidised to $B r_{2}$ by passing $C l_{2}$ which is a stronger oxidising agent.
$2 B r^{-} + C l_{2} + B r_{2} + 2 C l^{-}$

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