In the matrix, write :
$A = ⎡ ⎢ ⎢ ⎣ \begin{matrix} 235 \sqrt{3} \end{matrix} \begin{matrix} 5 - 2 1 \end{matrix} \begin{matrix} 19 \frac{5}{2} - 5 \end{matrix} \begin{matrix} - 7 1217 \end{matrix} ⎤ ⎥ ⎥ ⎦$

(i) The order of the matrix
(ii) The number of elements
(iii) Write the elements $a_{13}, a_{21}, a_{33}, a_{24}, a_{23}$

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Solution

(i) In the given matrix, the number of rows is $3$ and the number of columns is $4$ .
Therefore, the order of the matrix is $3 \times 4$ .
(ii) Since the order of the matrix is $3 \times 4$ , there are $3 \times 4 = 12$ elements in it.
(iii) $a_{13} = 19, a_{21} = 35, a_{33} = - 5, a_{24} = 12, a_{23} = \frac{5}{2}$

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In the matrix, write:

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In the matrix $⎡ ⎢ ⎢ ⎣ \begin{matrix} 2 & 5 & 19 & - 7 35 & - 2 & \frac{5}{2} & 12, \sqrt{3} & 1 & - 5 & 17 \end{matrix} ⎤ ⎥ ⎥ ⎦$ ,write
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(ii)The elements $a_{13}, a_{21}, a_{33}, a_{24}, a_{23} .$

In the matrix $⎡ ⎢ ⎢ ⎣ \begin{matrix} 2 & 5 & 19 & - 7 35 & - 2 & \frac{5}{2} & 12, \sqrt{3} & 1 & - 5 & 17 \end{matrix} ⎤ ⎥ ⎥ ⎦$ ,write
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Let

A = [a_{i j}] = ⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 4 & 8 6 & 2 & 5 3 & 7 & 0 9 & - 2 & - 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

. Find

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(ii) the elements

a_{13}

and

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(iii) the position of the element 2.

Q. In the matrix , write: (i) The order of the matrix (ii) The number of elements, (iii) Write the elements a 13 , a 21 , a 33 , a 24 , a 23

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In the matrix, write :A=⎡⎢ ⎢⎣235√35−211952−5−71217⎤⎥ ⎥⎦(i) The order of the matrix(ii) The number of elements (iii) Write the elements a13,a21,a33,a24,a23

(i) In the given matrix, the number of rows is 3 and the number of columns is 4.Therefore, the order of the matrix is 3×4.(ii) Since the order of the matrix is 3×4, there are 3×4=12 elements in it.(iii) a13=19,a21=35,a33=−5,a24=12,a23=52