In the mineral, barium ion can be identified by :

green colour in ame

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yellow precipitate with

C r O_{4}^{2 -}

solution

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white precipitate with

S O_{4}^{2 -}

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all of the above

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Solution

The correct option is B all of the above
${B a}^{2 +}$ ion in solution produces a yellow precipitate with $K_{2} C r O_{4}$
$B a^{2 +} + k_{2} C r O_{4} \to B a C r O_{4} ↓ + 2 K^{+}$

${B a}^{2 +}$ ions in solution produces a white precipitate with $(N H_{4})_{2} S O_{4}$ Solutions.
${B a}^{2 +} + (N H_{4})_{2} S O_{4} \to B a S O_{4} ↓ W h i t e p p t + 2 N H_{4}^{+}$

Hence option- (D) is correct.

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In the mineral, barium ion can be identified by :

The correct option is B all of the aboveBa2+ ion in solution produces a yellow precipitate with K2CrO4Ba2++k2CrO4→BaCrO4↓+2K+Ba2+ ions in solution produces a white precipitate with (NH4)2SO4 Solutions.Ba2++(NH4)2SO4→BaSO4↓Whiteppt+2NH+4Hence option- (D) is correct.