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Concentration Terms

In the mixtur...

Question

In the mixture of $N a H C O_{3}$ and $N a_{2} C O_{3}$ volume of a given HCl required is 'x' ml with phenolphthalein indicator and further 'y' ml required with methyl orange indicator. Hence volume of $H C l$ for complete reaction of $N a H C O_{3}$ is

A

2x

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B

y

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C

x/2

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D

(y - x)

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Solution

The correct option is D
(y - x)

$N a_{2} C O_{3} + H C l \to N a H C O_{3} + H C l$

$N a H C O_{3} + H C l \to N a C l + H_{2} O + C O_{2}$

Let ‘a’ milli equivalents of acid used at the first end point.

Milli equivalents acid = x = $\frac{1}{2}$ milli equivalents of $N a_{2} C O_{3}$

Let ‘b’ milli equivalents of acid used at the second end point.

Milli equivalents acid = y = $\frac{1}{2}$ milli eq. of $N a_{2} C O_{3}$ + 1 milli eq. of $N a H C O_{3}$

milli equivalents used by $N a_{2} C O_{3}$ = (2x)

milli equivalents of $N a H C O_{3}$ = (y - x)

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