Question

In the network shown in the figure, the equivalent resistance between A and C is

• A. $10R$
• B. $\left(6/11\right)R$
• C. $\left(12/15\right)R$
• D. $\left(50/11\right)R$

Answer 1

The correct option is D $\left(50/11\right)R$

$2R,R$ and $3R$ are in parallel, as they all are between same potential

$\frac{1}{R}+\frac{1}{2R}+\frac{1}{3R}-\frac{1}{R_p}\Rightarrow \frac{1}{R_p}=\frac{6+3+2}{6R}=\frac{11}{6R}$

$\frac{6R}{11}$ and $4R$ is in parallel, so

$\frac{6R}{11}+4R=\frac{6R+44R}{11}=\left(\frac{50}{11}\right)R$

$Re{q}_0=\left(\frac{50}{11}\right)R$