Question

In the network shown, which is part of a larger network, the potential at P is greater than Q by 43 V. The potential difference across the battery A is

• A. 6 V
• B. 4 V
• C. 2 V
• D. 8 V

Answer 1

The correct option is C

2 V

$V_P–(5+2+8+2)I+6–15=V_Q$

$V_P–V_Q=9+17I\Rightarrow I=2A$

$\therefore V_A=E-Ir=6–(2\times 2)=2v$