Question

In the non-relativistic regima, if the momentum, is increase by $100\%$, the percentage increase in kinetic energy is

Answer 1

Given that

In the non-relativistic regima, the momentum, is increase by $100$ %, t

As we know that

Kinetic energy , $K=\frac{p^2}{2m}$----------------------(1)

where $p$ is momentum and $m$ is mass

Percentage increase in momentum , $\frac{\Delta p}{p}\times 100=100$

$\frac{\Delta p}{p}=1$

From eq (1) Applying errors analysis

$\frac{\Delta K}{K}=2\frac{\Delta p}{p}=2$

Percentage increase in kinetic energy $=\frac{\Delta K}{K}\times 100$%=$200$%