Question

In the non-resonant circuit, what will be the nature of the circuit for frequencies higher than the resonant frequency?

• A. Inductive
• B. None of the above
• C. Capacitive
• D. Resistive

Answer 1

The correct option is A Inductive

Case of non-resonant circuit:
If ${\omega }_R$ is the resonant frequency
Then for $0<\omega <{\omega }_R;X_C>X_L$
Circuit is capacitive.
And for ${\omega }_R<\omega <\infty ;X_L>X_C$
Circuit is inductive
Thus, for frequencies higher than the resonant frequency the circuit would be inductive.
Hence, option $\left(C\right)$ is correct.