Question

In the nuclear change ${}_{92}\mathrm{U}^{235}+{}_{0}n^1$ → Fission products + neutron + 3.20 × 10^–11 J, the energy released when 1 g of ${}_{92}\mathrm{U}^{235}$ finally undergoes fission is
(a) 12.75 ​× 10⁸ kJ (b) 18.60 ​× 10⁹ kJ (c) 8.21 × 10⁷ kJ (d) 6.55 × 10⁶ kJ

Answer 1

Dear Student,

The computation are expressed below,

$$\begin{gathered} The1amuannihilationofmass=931.495MeV \\ Massdeficient=120.44MeV \\ energyreleaseper1gmis, \\ \frac{120.4MeV}{235.0439amu}\times \frac{1.6022\times {10}^{-19}MJ}{MeV}\times \frac{amu}{1gm}=8.17\times {10}^{7}kJ \end{gathered}$$

Hence the answer is Option (C) 8.21*10⁷ kJ

Regards.