Question

In the nuclear decay given below;
${}_Z^{A}X{\to }_{Z+1}^{A}Y{\to }_{Z-1}^{A-4}B\ast {\to }_{Z-1}^{A-4}B$
The particles emitted in the sequence are:

• A. $\alpha ,\beta ,\gamma$
• B. $\beta ,\alpha ,\gamma$
• C. $\gamma ,\beta ,\alpha$
• D. $\beta ,\gamma ,\alpha$

Answer 1

Answer: (B)

$\beta ,\alpha ,\gamma$

$\cdot \alpha -$decay

$Z^{X^A}\stackrel{\alpha }{\to }{Z-2}^{X^{A-4}}$

$\cdot \beta -$decay

$Z^{X^A}\stackrel{\beta }{\to }{Z+1}^{X^A}$

$\cdot \gamma -$decay consists of electromagnetic radioations.

Now, the given decay series.

$Z^{X^A}\underrightarrow{\beta }{Z+1}^{Y^A}\underrightarrow{\alpha }{Z-1}^{B^{A-4}}\underrightarrow{\gamma }{Z-1}^{B^{A-4}}$

$\therefore$ The correct sequence.

$\beta ,\alpha ,\gamma$