In the nuclear reaction- 13 Al27 - 2He4 - 14 X30 - 1H1- X is-

The correct option is A SiIn the nuclear reaction #160; _13 Al^27 + _2He^4 → _14X^30 + _1H^1 ,X is Silicon with mass number 30 and atomic number 14. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Ionization Enthalpy

In the nuclea...

Question

In the nuclear reaction, $_{13} A l^{27} +_{2} H e^{4} \to_{14} X^{30} +_{1} H^{1}, X$ is:

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Si
In the nuclear reaction

$_{13} A l^{27} +_{2} H e^{4} \to_{14} X^{30} +_{1} H^{1}$ ,

X is Silicon with mass number 30 and atomic number 14.

$_{13} A l^{27} +_{2} H e^{4} \to_{14} S i^{30} +_{1} H^{1}$ .

Hence, option A is correct.

Suggest Corrections

Similar questions

Q. In the nuclear reaction given by

_{2} H e^{4} +_{7} N^{14} \to_{1} H^{1} + X

the nucleus X is

Q. Which of the following particles is emitted in the nuclear reaction :

_{13} A l^{27} +_{2} h e^{4} \to_{14} P^{30} + . . . . . .

_{7} N^{14} +_{2} H e^{4} \to

X+

_{1} H^{1}

; X is

_{7} M^{14} +_{2} H e^{4} \to X +_{1} H^{1}, X

is:

Q. Which of the following particle is emitted in the reaction

_{13} A l^{27} +_{2} H e^{4} \to_{14} P^{30} +

....

Join BYJU'S Learning Program

In the nuclear reaction, 13Al27+2He4→14X30+1H1,X is:

The correct option is A SiIn the nuclear reaction 13Al27+2He4→14X30+1H1,X is Silicon with mass number 30 and atomic number 14.13Al27+2He4→14Si30+1H1.Hence, option A is correct.

In the nuclear reaction, $_{13} A l^{27} +_{2} H e^{4} \to_{14} X^{30} +_{1} H^{1}, X$ is:

The correct option is A Si
In the nuclear reaction

$_{13} A l^{27} +_{2} H e^{4} \to_{14} X^{30} +_{1} H^{1}$ ,

X is Silicon with mass number 30 and atomic number 14.

$_{13} A l^{27} +_{2} H e^{4} \to_{14} S i^{30} +_{1} H^{1}$ .

Hence, option A is correct.