Question

In the nuclear reaction given by ${}_{2}H{e}^4{+}_7{N}^{14}{\to }_1{H}^1+X$ the nucleus X is

• A. nitrogen of mass $16$
• B. nitrogen of mass $17$
• C. oxygen of mass $16$
• D. oxygen of mass $17$

Answer 1

Answer: (D)

oxygen of mass $17$

${}_{2}H{e}^4{+}_7{N}^{14}{\to }_1{H}^1{+}_Z{X}^A$

Mass Balance:
$4+14=1+A$
$A=17$

Charge balance:
$2+7=1+Z$
$Z=8$

Element of atomic no. $8$ and mass $17$ - Oxygen