Question

In the nuclear reaction $U^{235}{+}_0{n}^1{⟶}_{56}B{a}^{141}{+}_{36}K{r}^{92}$+3X+200 MeV,

X represents

• A. proton
• B. neutron
• C. electron
• D. alpha particle

Answer 1

The correct option is B neutron

When $U^{235}$ is bombarded with a thermal neutron, it breaks into $B{a}^{141}$ and $K{r}^{141}$ along with the liberation of 3 neutrons, this is how the fission of $U^{235}$ takes place.

The fission reaction is:

$U^{235}{+}_0{n}^1{⟶}_{56}B{a}^{141}{+}_{36}K{r}^{92}+3_0{n}^1+200MeV$