Question

In the nuclear transmutation, ${}_4^{9}Be+X{\to }_4^{8}Be+Y$ X and Y are:

• A. $(\gamma ,n)$
  
• B. $(p,D)$
• C. $(n,D)$
• D. $(\gamma ,p)$

Answer 1

Answer: (A), (B)

$(p,D)$

Plan
${}_4^{9}Be{+}_a^{b}X{\to }_4^{8}Be{+}_c^{d}Y$
Atomic number same
4+a=4+c
9+b=8+d
If $X{=}_0^0\gamma$ a = 0
b = 0
$Y{=}_0^{1}n$ c = 0
d = 1
If $X{=}_1^{1}p$ a = 1
b = 1
$Y{=}_1^{2}D$ c = 1
d = 2
${}_4^{9}Be{+}_0^0\gamma {\to }_4^{8}Be{+}_0^{1}n$
${}_4^{9}Be{+}_1^{1}p{\to }_4^{8}Be{+}_1^{2}D$