Question

In the obtuse triangle ABC, AM = MB, $MD\perp BC,EC\perp BC$ If the area of $\Delta ABC$ is 24 then the area of $\Delta BED$ is

• A. 9
• B. 12
• C. 15
• D. 18

Answer 1

The correct option is B 12

M is mid point of $AB$.

Therefore $AM=MB$ and $CM$ is median.

$△BMC=\frac{1}{2}△ABC=\frac{1}{2}\times 24=12$

$Areaof△CDM=Areaof△DME$

$Areaof△BED=△BMD+△MDE$

$Areaof△BED=△BMD+△CDM$

$Areaof△BED=Areaof△BMC$

$=12Sq.unit$