Question

In the Orion stellar system the shining of a star is $17\times {10}^3$ times that of the sun. If the temperature of the surface of the sun $6\times {10}^{3}K$ then the temperature of this star will be

• A. 273 K
• B. 652 K
• C. 6520 K
• D. 68520 K

Answer 1

The correct option is D 68520 K

The power radiated is directly proportional to the fourth power of the absolute temperature.
$P\propto T^4$
$P=k{T}^4$

Let P = Power radiated by the sun
Power radiated by star $=17\times {10}^{3}P$
$\frac{T_{star}^4}{T_{sun}^4}=17\times {10}^3$
$\frac{T_{star}}{T_{sun}}=11.418$
$T_{star}=6000\times 11.418=68,511K$

Hence, the answer is option D.