In the oscillation of a spring - block system on a smooth horizontal surface- match the entries of column I with the entries of column - II-WlineColumn - I - Column - IIM Wlinea If mass of the vlock is doubled - P Energy of oscillation becomes four timesll Wlineb If amplitude of oscillation is - Q Maximum speed of particle vecome 2 timesll Wlinec If force constant is doubled - R Time period becomes usqrt 2 timesll Wlined If angular frequency is woubled - S Potential energy at cextreme position becomes 2 ctimesWline array A- a-P Q - b-R - c-P Q - D-SB- a-R - b-P Q - c-S - D-P QC- a-S - b-R - c-S - P Q-DD- a - S - b - R - c - S - D - PQ

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Relating Circular Motion to SHM

In the oscill...

Question

In the oscillation of a spring – block system on a smooth horizontal surface, match the entries of column I with the entries of column – II.
$\begin{matrix} C o l u m n - I & C o l u m n - I I (a) I f m a s s o f t h e b l o c k i s d o u b l e d & (P) E n e r g y o f o s c i l l a t i o n b e c o m e s f o u r t i m e s (b) I f a m p l i t u d e o f o s c i l l a t i o n i s d o u b l e d & (Q) M a x i m u m s p e e d o f p a r t i c l e b e c o m e 2 t i m e s (c) I f f o r c e c o n s t a n t i s d o u b l e d & (R) T i m e p e r i o d b e c o m e s \sqrt{2} t i m e s (d) I f a n g u l a r f r e q u e n c y i s d o u b l e d & (S) P o t e n t i a l e n e r g y a t e x t r e m e p o s i t i o n b e c o m e s 2 t i m e s \end{matrix}$

a – PQ ; b – R ; c – PQ ; D – S

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a – R ; b – PQ ; c – S ; D – PQ

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a – S ; b – R ; c – S ; D – PQ

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a – S ; b – R ; c – S ; PQ – D

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Solution

The correct option is B a – R ; b – PQ ; c – S ; D – PQ
a – R ; b – PQ ; c – S ; D – PQ
f mass of the block is doubled, Time period becomes 2 times AND If amplitude of oscillation is doubled, Energy of oscillation becomes four times and Maximum speed of particle become 2 times

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The correct option is B a – R ; b – PQ ; c – S ; D – PQa – R ; b – PQ ; c – S ; D – PQ f mass of the block is doubled, Time period becomes 2 times AND If amplitude of oscillation is doubled, Energy of oscillation becomes four times and Maximum speed of particle become 2 times

The correct option is B a – R ; b – PQ ; c – S ; D – PQ
a – R ; b – PQ ; c – S ; D – PQ
f mass of the block is doubled, Time period becomes 2 times AND If amplitude of oscillation is doubled, Energy of oscillation becomes four times and Maximum speed of particle become 2 times