In the oxidation of alkenes with which solution followed by acidification with dilute $H_{2} {S O}_{4}$ gives diol?

N a O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{K M n O}_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H_{2} {S O}_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C ${K M n O}_{4}$
In the oxidation of alkene is performed in presence of acidic $K M n O_{4}$ , first diol forms which further oxidize to form ketone/aldehyde and by further oxidation of this acid will be formed as the final product.
The reaction is as follow:
$C H_{2} = C H_{2}$ + $H_{2} O$ + $[O] K M n O_{4} - ---- \to C H_{2} O H - C H_{2} O H$

Suggest Corrections

Similar questions

K_{2} {C r}_{2} O_{7} + K I + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {C r}_{2} {({S O}_{4})}_{3} + I_{2} + H_{2} O

K M n O_{4} + {N a}_{2} {S O}_{3} \to M n O_{2} + {N a}_{2} {S O}_{4} + K O H

C u + H {N O}_{3} \to C u {({N O}_{3})}_{2} + {N O}_{2} + H_{2} O

K M {n O}_{4} + H_{2} C_{2} O_{4} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {M n S O}_{4} + {C O}_{2} + H_{2} O

(H_{2} O_{2})

(H_{2} {S O}_{4})

H_{2} {S O}_{4}

H_{2} {S O}_{4}

H_{2} {S O}_{4}

5 m L

3 N

H_{2} {S O}_{4}

245 m L

Join BYJU'S Learning Program