In the P-V diagram shown in figure, ABC is a semicircle. The work done in the process ABC is
A
Zero
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B
π2 atm L
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C
−π2 atm L .
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D
4 atm L .
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Solution
The correct option is Bπ2 atm L WAB is negative (volume is decreasing) and WBC is positive (volume is increasing) and since, |WBC|>|WAB| ∴ Net work done is positive and area between semicircle which is equal to π2 atm L .