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Question

In the parallelogram ABCD, ΔAOB is congruent to


A

ΔABC

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B

ΔAOC

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C

ΔAOB

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D

ΔCOD

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Solution

The correct option is D

ΔCOD


AB = CD ( Opposite sides in a parallelogram are equal)

ABD = BDC (Alternate angles)

and OB = OD ( Diagonals of a parallelogram bisect each other)

From SAS congruency we can say that ΔAOB is congruent to ΔCOD


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