In the parallelogram ABCD the angles A and C are obtuse Points X and Y are taken on the diagonal BD such that the angles XAD and YCB are right angles.
And hence, $X A = Y C$
If the above statement is true then mention answer as 1, else mention 0 if false

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Solution

In $△ X A D$ and $△ Y C B$
$∠ X A D = ∠ Y C B$ (Given each $90^{\circ}$ )
$A D = B C$ (Opposite sids of parallelogram are equal)
$∠ X D A = ∠ Y B C$ (Alternate angles of parallel lines AD and BC)
$△ X A D ≅ △ Y C B$ (ASA rule)
Thus, $X A = Y C$ (Corresponding sides)

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Similar questions

In the parallelogram ABCD, the angles A and C are obtuse. Points X and Y are taken on the diagonal BD such that the angles XAD and YCB are right angles.

Prove that: XA = YC.

State whether the above statement is true or false.

Q. The sides PQ, PR of triangle PQR are equal, and S,T are points on PR,PQ such that

∠ P S Q a n d ∠ P T R

are right angles.
And hence, the triangles PSR and PSQ are congruent
If the above statement is true then mention answer as 1, else mention 0 if false

Q. ABCD is a square P,Q and R are the points on AB, BC and CD respectively; such that AP=BQ=CR.
Hence, PB=QC
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Quadrilateral ABCD is a square. X is the mid-point of AB and Y is the mid-point of BC. Hence, $∠ D X A = ∠ A Y B$

If the above statement is true then mention answer as 1, else mention 0 if false

Hence, $Δ A D C$ and $Δ B A C$ are similar.

If the above statement is true then mention answer as 1, else mention 0 if false

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In the parallelogram ABCD the angles A and C are obtuse Points X and Y are taken on the diagonal BD such that the angles XAD and YCB are right angles.And hence, XA=YCIf the above statement is true then mention answer as 1, else mention 0 if false

In △XAD and △YCB∠XAD=∠YCB (Given each 90∘)AD=BC (Opposite sids of parallelogram are equal)∠XDA=∠YBC (Alternate angles of parallel lines AD and BC)△XAD≅△YCB (ASA rule)Thus, XA=YC (Corresponding sides)

In the parallelogram ABCD the angles A and C are obtuse Points X and Y are taken on the diagonal BD such that the angles XAD and YCB are right angles.
And hence, $X A = Y C$
If the above statement is true then mention answer as 1, else mention 0 if false

In $△ X A D$ and $△ Y C B$
$∠ X A D = ∠ Y C B$ (Given each $90^{\circ}$ )
$A D = B C$ (Opposite sids of parallelogram are equal)
$∠ X D A = ∠ Y B C$ (Alternate angles of parallel lines AD and BC)
$△ X A D ≅ △ Y C B$ (ASA rule)
Thus, $X A = Y C$ (Corresponding sides)