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Question

In the picture below, the radius of the circle is 15 centimetres. Compute the lengths of the tangents PQ and PR

(i) The point P is equidistant from A and B

(ii) The line OP bisects the line AB and the angle APB

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Solution

Given: OR = OQ = 15 cm and ROQ = 120°

Construction: Join OP.

In ΔOPR and ΔOPQ:

OR = OQ (Radii of the same circle)

OP = OP (Common side)

PR = PQ (Length of tangents drawn from a point outside the circle are equal)

If all the sides of one triangle are equal to the corresponding sides of the other triangle then the two triangles are congruent.

∴ ΔOPR ΔOPQ

⇒ ∠POR = POQ (Congruent parts of congruent triangles are congruent)

⇒ ∠POR = POQ =

In ΔPOR:

= tan 60°

RP = OR tan 60°

= 15 cm ×

= 15 × 1.732 cm

= 25.98 cm

We know that lengths of tangents drawn from an external point are equal.

PQ = PR = 25.98 cm


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