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Question

In the polar aprotic solvent, the increasing order of nucleophilicity of the following is:

HO−, HS−, HSe−

A
HO<HSe<HS
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B
HO=HS=HSe
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C
HO<HS<HSe
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D
HO>HS<HSe
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Solution

The correct option is B HO<HS<HSe
In the polar aprotic solvent, the increasing order of nucleophilicity is HO<HS<HSe.
The decreasing order of electronegativity is O>S>Se. In the hydroxide ion, the negative charge is present on more electronegative O atom as compared to Se atom in hydroselenide ion. Hence, the negative charge can be less readily donated by hydroxide ion than by hydroselenide ion.

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