Question

In the preparation of $AgI$ sol, the excess of $AgN{O}_3$, is added to potassium iodide solution. The particles of the sol will acquire –

• A. Negative charge
• B. Positive charge
• C. No charge
• D. Unpredictable

Answer 1

The correct option is A Negative charge

If $AgN{O}_3$ solution is added to $KI$ solution, the precipitated silver iodide $\left(AgI\right)$ will adsorb iodide ions from the dispersion medium and this will acquire negative charge.

$AgN{O}_3+KI\left(\text{excess}\right)\to AgI\stackrel{AgN{O}_3}{\to }AgI/I^{-}$