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Question

In the preparation of CaO from CaCO3 using the equilibrium
CaCO3(s)CaO(s)+CO2(g)
Kp is expressed as
logKp=7.2828500T
for the complete decomposition of CaCO3, the temperature in celsius to be used is____________.

A
1167oC
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B
894oC
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C
8500oC
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D
850oC
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Solution

The correct option is A 894oC
In the preparation of CaO from CaCO3 using the equilibrium
CaCO3(s)CaO(s)+CO2(g)
Kp is expressed as
logKp=7.2828500T
For complete decomposition Kp=1
logKp=0
logKp=7.2828500T
0=7.2828500T
7.282=8500T
T=1167.26K
T=1167.26273.15oC
T=894.11oC
Thus, for the complete decomposition of CaCO3, the temperature in celsius to be used is T=894oC

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