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Oxides of Sulphur

In the prepar...

Question

In the preparation of $C l_{2}$ from $H C l$ and $M n O_{2}$ , $M n O_{2}$ acts as:

catalyst

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reducing agent

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oxidising agent

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none of the above

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Solution

The correct option is B oxidising agent
$M n O_{2} + 4 H C l \to M n C l_{2} + 2 H_{2} O + C l_{2}$
In the above reaction $M n O_{2}$ is reduced to $M n^{+ 2}$ and oxidation number decreases from +4 to +2, thus it acts as oxidising agent.

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C l_{2}

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4 H C l + M n O_{2} \to M n C l_{2} + 2 H_{2} O + C l_{2}

(M n O_{2})

M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O

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