Question

In the preparation of copper sulfate from copper, oxidation state of copper changes from:

• A. $+1$ to $+2$
• B. $0$ to $+2$
• C. $+2$ to $+1$
• D. $+2$ to $0$

Answer 1

Answer: (B)

$0$ to $+2$

$Cu\left(g\right)+H_{2}S{O}_4\left(l\right)\to CuS{O}_4\left(aq\right)+S{O}_2\left(g\right)+2H_{2}O\left(l\right)$

In elemental state oxidation state of copper is zero, and in $CuS{O}_4$ it is $C{u}^{+2}$ and $S{O}_4^{-2}$.