In the preparations of ethyl chloride by Grooves- method- CH3CH2OH - HCl CH3CH2Cl - H2O the main reason for using anhydrous ZnCl2 as catalyst is that

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Preparation of Haloalkanes from Alcohol

In the prepar...

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In the preparations of ethyl chloride by Grooves’ method, $C H_{3} C H_{2} O H + H C l A n h y d . Z N C l_{2} - ------- \to C H_{3} C H_{2} C l + H_{2} O$ the main reason for using anhydrous $Z n C l_{2}$ as catalyst is that

it absorbs water thereby pushing the equilibrium to the right

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it coordinates with the product

C H_{3} C H_{2} C l

and

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it helps in producing the nucleophile

C l^{-}

from HCl

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it coordinates with oxygen of ethyl alcohol and thus increases the leaving group ability of the –OH group

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C H_{3} C H_{2} O H + H C l anhydrous - ----- \to Z n C l_{2} C H_{3} C H_{2} C l + H_{2} O

Z n C l_{2}

C H_{3} C H_{2} O H + H C l A n h y d . Z N C l_{2} - ------- \to C H_{3} C H_{2} C l + H_{2} O

Z n C l_{2}

$C H_{3} C H_{2} O H + H C l Z n C l_{2} - --- \to C H_{3} C H_{2} C l + H_{2} O$ In the above reaction, the leaving group is ?

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