Question

In the presence of a small amount of water, $PC{l}_5$ hydrolyses to form:

• A. $PC{l}_3$
• B. $H_{3}P{O}_3$
• C. $POC{l}_3$
• D. $POCl$

Answer 1

The correct option is C $POC{l}_3$

In small amount of water, $PC{l}_5+H_{2}O\to POC{l}_3+2HCl$

It finally get converted to phosphoric acid in excess of water.
$POC{l}_3+H_{2}O\to H_{3}P{O}_4+3HCl$