In the presence of a small amount of water, $P C l_{5}$ hydrolyses to form:

P C l_{3}

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H_{3} P O_{3}

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P O C l_{3}

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P O C l

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Solution

The correct option is C $P O C l_{3}$
In small amount of water, $P C l_{5} + H_{2} O \to P O C l_{3} + 2 H C l$

It finally get converted to phosphoric acid in excess of water.
$P O C l_{3} + H_{2} O \to H_{3} P O_{4} + 3 H C l$

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In the presence of a small amount of water, PCl5 hydrolyses to form:

The correct option is C POCl3In small amount of water, PCl5+H2O→POCl3+2HCl It finally get converted to phosphoric acid in excess of water. POCl3+H2O→H3PO4+3HCl

In the presence of a small amount of water, $P C l_{5}$ hydrolyses to form:

The correct option is C $P O C l_{3}$
In small amount of water, $P C l_{5} + H_{2} O \to P O C l_{3} + 2 H C l$

It finally get converted to phosphoric acid in excess of water.
$P O C l_{3} + H_{2} O \to H_{3} P O_{4} + 3 H C l$