In the presence of peroxide, HCl and HI do not give anit-Markownikoff's addition to alkenes because:
A
one of the steps is endothermic in HCl and HI
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B
both HCl and HI are strong acids
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C
HCl is oxidizing and the HI is reducing
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D
all the steps are exothermic in HCl and HI
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Solution
The correct option is B one of the steps is endothermic in HCl and HI In the presence of organic peroxides, bromides will take part in radical based reactions. Fission of the peroxide O-O linkage will induce a Br radical which behaves differently to Bromide, by adding to the less substituted side of the alkene (anti - markovnikov). HI and HCl do not do this for energetic reasons.
The addition of Cl and I radicals to the alkene in an anti-markovnikov fashion is an endothermic reaction and therefore unfavourable. Without the presence of peroxide, all hydrogen halides will add according to the markovnikov rule. Hence, option A is the correct answer.