In the process of construction of an angle with P as the centre and any radius, draw an arc as shown, which cuts in A. This is the first arc. With A as centre and the same radius, cut this arc in B. This would be the second arc. What will be the value of $∠ B P A$ in degrees?

60

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Solution

The correct option is A 60
Since we draw all these arcs with the same radius, it follows that PA = PB = AB. Hence $△$ ABP is equilateral and hence $∠$ BPA = $60^{\circ}$

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Q. In the process of construction of an angle with P as the centre and any radius, draw an arc as shown, which cuts in A. This is the first arc. With A as centre and the same radius, cut this arc in B. This would be the second arc. What will be the value of

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In the process of construction of an angle with P as the centre and any radius, draw an arc as shown, which cuts in A. This is the first arc. With A as centre and the same radius, cut this arc in B. This would be the second arc. What will be the value of ∠BPA in degrees? 60

The correct option is A 60Since we draw all these arcs with the same radius, it follows that PA = PB = AB. Hence △ ABP is equilateral and hence ∠ BPA = 60∘

In the process of construction of an angle with P as the centre and any radius, draw an arc as shown, which cuts in A. This is the first arc. With A as centre and the same radius, cut this arc in B. This would be the second arc. What will be the value of $∠ B P A$ in degrees?

60

The correct option is A 60
Since we draw all these arcs with the same radius, it follows that PA = PB = AB. Hence $△$ ABP is equilateral and hence $∠$ BPA = $60^{\circ}$