In the process of extraction of gold, the following reaction takes places: $Roasted gold ore + C N^{-} + O_{2} + 2 H_{2} O \to [X] + O H^{-}$
$[X] + Z n \to [Y] + A u$
Identify the compounds [X] and [Y].

[X] = [A u (C N)_{4}]^{3 -}, [Y] = [Z n (C N)_{4}]^{2 -}

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[X] = [A u (C N)_{2}]^{-}, [Y] = [Z n (C N)_{4}]^{2 -}

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[X] = [A u (C N)_{4}], [Y] = [Z n (C N)_{6}]^{2 -}

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[X] = [A u (C N)_{2}]^{-}, [Y] = [Z n (C N)_{6}]^{4 -}

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Solution

The correct option is B $[X] = [A u (C N)_{2}]^{-}, [Y] = [Z n (C N)_{4}]^{2 -}$
In the metallurgy of silver and that of gold, the respective metal is leached with a dilute solution of NaCN or KCN in the presence of air (for $O_{2}$ ) from which the metal is obtained later by replacement:
$4 Roasted gold ore + 8 C N^{-} + O_{2} (g) + 2 H_{2} O (a q) \to [A u (C N)_{2}]^{-} (a q) + 4 O H^{-} (a q)$
$2 [A u (C N)_{2}]^{-} (a q) + Z n (s) \to [Z n (C N)_{4}]^{2 -} (a q) + 2 A u (s)$
Hence, $[X] = [A u (C N)_{2}]^{-} and [Y] = [Z n (C N)_{4}]^{2 -}$
Hence option (a) is correct.

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