Question

In the process of respiration, in plants, 180 gm of glucose and 192 gm of oxygen produces

• A. 132 gm of CO${}_2$, 54 gm of H${}_2$O and 483 Cal of energy.
• B. 264 gm of CO${}_2$, 108 gm of H${}_2$O, and 686 KCal of energy.
• C. 200 gm of C${}_2$H${}_5$OH, 72 gm of H${}_2$O and 21 KCal of energy.
• D. None of the above.

Answer 1

The correct option is B 264 gm of CO${}_2$, 108 gm of H${}_2$O, and 686 KCal of energy.

The values of reactants are given in grams. We can convert them to moles by using the simple formula- the number of moles is equal to weight in grams divided by molecular weight. The chemical formula of glucose is C${}_6$H${}_{12}$O${}_6$, so the molecular weight of glucose works out to be 180 and we know the molecular weight of diatomic oxygen is 32. On substituting the values, we come to know that question is asking about products formed when one molecule of glucose is reacting with six molecules of oxygen. When one molecule of glucose is completely oxidized in aerobic respiration it gives rise to six molecules of carbon dioxide (6x 44 i.e., 264 grams) and six molecules of water (6x 18 i.e., 108 grams) and releases 686 Kcal of energy.

So, the correct answer is option B.