In the product of 459 - 46 - 28 - - 484- the digit in the units- place is 2- The digit to come in place of - is

The correct option is C 7 Multiplying the units' digit of 459, 46 and 484 we get #160; 9 × 6 × 4 = 216 whose units' digit is 6 So, ...

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Byju's Answer

Standard VII

Mathematics

Addition and Subtraction of Integers

In the produc...

Question

In the product of $459 \times 46 \times 28 * \times 484$ , the digit in the units' place is $2.$ The digit to come in place of $*$ is

3

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Solution

The correct option is C $7$
Multiplying the units' digit of $459, 46 a n d 484$
we get $9 \times 6 \times 4 = 216$ whose units' digit is $6$
So, $*$ should be replaced by $7$ $(∵ 6 \times 7 = 42)$ to
get $2$ as the units' digit in the final product

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In the product of 459×46×28∗×484, the digit in the units' place is 2. The digit to come in place of ∗ is

The correct option is C 7Multiplying the units' digit of 459,46 and 484we get 9×6×4=216 whose units' digit is 6So, ∗ should be replaced by 7 (∵6×7=42) toget 2 as the units' digit in the final product

In the product of $459 \times 46 \times 28 * \times 484$ , the digit in the units' place is $2.$ The digit to come in place of $*$ is

The correct option is C $7$
Multiplying the units' digit of $459, 46 a n d 484$
we get $9 \times 6 \times 4 = 216$ whose units' digit is $6$
So, $*$ should be replaced by $7$ $(∵ 6 \times 7 = 42)$ to
get $2$ as the units' digit in the final product