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Question

In the product of expression of(1+2x)6(1x)7, find the coefficient of x5?

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Solution

(1+2x)6=6C01+6C1(2x)+6C2(2x)2+6C2(2x)3+6C4(2x)4+6C5(2x)5+6C6(2x)6

=1+12x+60x2+20×8x3+15×16x4+6×32x6+64x5

=1+12x+60x2+160x3+240x4+192x5+64x6

(1x)7=17C1x+C2x2C3x3+7C4x47C5x5+7C6x67C7x7

17x+12x235x3+35x421x5+7x6x7(2)

Coefficient of x5 in the product (1+2x)6(1x)7

=1×21+12×35+60×35+160×21+240×7+192×1

=21+4202100+33601680+192

=171

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