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Question

In the quadratic equation ax2+bx+c=0, if Δ=b24ac, then α+β,α2+β2,α3+β3 are?

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Solution

α+β=ba......(1)

α2+β2=(α+β)22αβ

=(ba)22ca

α2+β2=b22aca2.......(2)

α3+β3=(α+β)(α2αβ+β2)

=(ba)(b22aca2ca)

α3+β3=b33abca3........(3)

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